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In general, no one alive or dead can find the solution to a nonlinear differential equation. The reason so much time is spent studying linear differential equations is not because nonlinear differential equations are less important, it's that nonlinear differential equations are nearly impossible to solve. Sometimes though, specific forms of nonlinear differential equations can be solved. This is so rare that the differential equations will be named. One of those types of equations is Bernoulli equations.
A Bernoulli differential equation has the following form,
\begin{equation} y' + p(x)y = g(x)y^{n} \end{equation}where $n$ is any real number except 0 or 1 because $n=0$ means the RHS is just $g(x)y^{0}=g(x)$ and $n=1$ is also linear by combining the $p(x)y$ and $g(x)y$ into one $(p(x)-g(x))y$ term.
Using the substitution $u = y^{1-n}$ results in a linear differential equation.
\begin{equation} u = y^{1-n} \qquad u' = (1-n)y^{-n}y' \end{equation} \begin{equation} y' + p(x)y = g(x)y^{n} \qquad u' + (1-n)p(x)u = (1-n)g(x) \end{equation}Find the general solution to the Bernoulli differential equation.
\begin{equation} y' - 3y = -y^{2} \end{equation}Find the general solution to the Bernoulli differential equation.
\begin{equation} y' - \frac{y}{x} = -x^{2}y^{-3} \end{equation}Find the general solution to the Bernoulli differential equation.
\begin{equation} y' + y = \sqrt{y} \end{equation}Find the general solution to the Bernoulli differential equation.
\begin{equation} y' + y = e^{x} y^{\frac{3}{7}} \end{equation}Another common substitution problem is $u = \dfrac{y}{x}$ but the problems always seem a little made up.
Find the general solution to the following differential equation.
\begin{equation} x^{2}y' = y^{2} + xy \end{equation}Find the general solution to the following differential equation.
\begin{equation} x^{2}y' = y^{2} + xy + x^{2} \end{equation}Lastly, some differential equations were intentionally made for a particular substitution.
Find the general solution to the following differential equation.
\begin{equation} yy' + x = \sqrt{x^{2}+y^{2}} \end{equation}Find the general solution to the following differential equation.
\begin{equation} y' = (x+y+4)^{2} \end{equation}